IRS2540 [INFINEON]

IRPLLED1 High Voltage LED Driver using the IRS2540; 采用IRS2540 IRPLLED1高电压LED驱动器
IRS2540
型号: IRS2540
厂家: Infineon    Infineon
描述:

IRPLLED1 High Voltage LED Driver using the IRS2540
采用IRS2540 IRPLLED1高电压LED驱动器

驱动器
文件: 总28页 (文件大小:826K)
中文:  中文翻译
下载:  下载PDF数据表文档文件
IRPLLED1  
IRPLLED1 High Voltage LED Driver using the IRS2540  
Table of Contents  
Page  
1. Introduction………………………………………………………………...….1  
2. Constant Current Control.......................................................................3  
3. Frequency Selection..............................................................................6  
4. Output L1 and COUT Selection ................................................................6  
5. FET vs. Diode for the Low-Side Switch.………………………………….12  
6. VCC Supply ...…………………………………………….………………….15  
7. VBS Supply ……………………………………………….………………….16  
8. Enable Pin ……….………………………….……………………………….17  
9. Other Design Considerations .…………….……………………………….23  
10. Design Procedure Summary ……….…………………………………….24  
11. Bill of Materials ………………………..……………………………….24-26  
12. PCB Layout ………………………………………………………………...26  
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1. Introduction  
As the industry becomes more power conscious to compensate for increasing energy costs and to meet  
governmental regulations, new innovative ways of conserving energy are being developed. For the  
lighting industry one of these outlets has been LEDs. Due to their longevity, robust design, low  
maintenance and high efficiency, they have proven to be a viable alternative to less efficient light  
sources. With their long term projected falling cost and further increased efficiency, the industry has  
eagerly embraced LEDs and put them in high demand. LEDs require drivers that have specific  
features such as constant current control over the temperature and manufacturing variations of LEDs,  
dimming, and appropriate fault protections. The IRS254(0,1) is specifically designed to address these  
requirements  
The IRPLLED1 evaluation board is a high voltage LED driver designed to operate on an input DC  
voltage of 40 V to 170 V and supply a programmable load current of 350 mA, 700 mA, 1 A, or 1.5 A.  
The output voltage is also clamped at 30 V by the external open-circuit-protection circuitry, which can  
easily be disabled or reconfigure as explained in this reference design. However the output voltage  
should not exceed the ratings of the external components mounted on the board; higher voltage when  
optimized components are utilized in the design. IRPLLED1 uses the IRS254(0,1), a high voltage, high  
frequency buck control IC for constant LED current regulation. The IRS254(0,1) controls the average  
load current by a continuous mode time-delayed hysteretic method using an accurate on chip band gap  
voltage reference. The 8-pin, 200 V (600 V) rated IRS2540 (IRS2541) inherently provides short-circuit  
protection, with open-circuit protection incorporated by a simple external circuit and has full dimming  
capabilities. The IRS254(0,1) allows scalable designs to accommodate series and parallel  
configurations of LEDs, for today’s production LEDs as well as new generation higher current LEDs,  
and provides high current control accuracy over input and output voltage.  
The evaluation board documentation will briefly describe the functionality of IRS254(0,1), discuss the  
selection of the output stage, of the switching components, and of the surrounding circuitry. This board  
was tested with a single Lumileds™ flood board for the 350 mA and 700 mA settings, and two  
Lumileds flood boards in parallel for the 1 A and 1.5 A settings. Lumileds flood boards are available  
through Future Electronics and have a max nominal current rating of 700 mA with a breakdown  
voltage between 16 V and 24 V. This demo board can operate off of a 120 V AC rectified line with  
the addition of a proper rectifying circuit.  
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2. Constant current control  
The IRS254(0,1) is a time-delayed hysteretic buck controller. During normal operating conditions the  
output current is regulated via the IFB pin voltage, nominal value of 500 mV. This feedback is  
compared to an internal high precision band gap voltage reference. An on-board dV/dt filter has also  
been used to prevent erroneous transitioning.  
Once the supply to the chip reaches  
, the LO output is held high and the HO output is low for a  
VCCUV+  
predetermined period of time. This initiates the charging of the bootstrap capacitor, establishing the  
VBS floating supply for the high-side output. Then the chip begins toggling HO and LO outputs as  
needed to regulate the current. The deadtime of approximately 140 ns between the LO and HO gate  
drive signals prevents “shoot-through” and reduce switching losses, particularly at higher frequencies.  
VBUS  
L2  
VOUT+  
RS1  
RS2  
DBOOT  
IC1  
VCC  
COM  
VB  
HO  
VS  
LO  
CVCC1  
1
2
3
4
8
7
6
5
ROV1  
ROV2  
RG1  
M1  
M2  
DCLAMP  
CVCC2  
CBUS2  
CBOOT  
L1  
IFB  
CBUS1  
DOV  
CEN  
ENN  
RG2  
COUT  
VOUT-  
RCS  
RF  
ROUT  
CF  
COM  
EN  
DEN1  
Fig. 1: IRS254(0,1) Constant Current LED Driver Typical Schematic  
(see Fig. 16 for evaluation board schematic)  
Note: Rout is needed only in few applications  
Under normal operating conditions, if VIFB is below VIFBTH, HO is on and the load is receiving current  
from VBUS. This simultaneously stores energy in the output stage, L1 and COUT, whilst VIFB begins to  
increase. Once VIFB crosses VIFBTH, HO switches off after the delay tHO,off. Once HO is off, LO will  
turn on after the deadtime, the inductor and output capacitor release the stored energy into the load and  
VIFB starts decreasing. When VIFB crosses VIFBTH again, LO switches off after the delay tLO,off and HO  
switches on after the delay tHO,on  
.
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(A)  
(B)  
Fig. 2: (A) Storing Energy in Inductor  
(B) Releasing Stored Inductor Energy  
Fig. 3: IRS254(0,1) Control Signals, Iavg=1.2 A  
50%  
HO  
50%  
50%  
t_HO_off  
t_HO_on  
DT2  
DT1  
50%  
50%  
LO  
t_LO_off  
t_LO_on  
IFB  
IFBTH  
Fig. 4: IRS254(0,1) Time Delayed Hysteresis  
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The switching continues to regulate the current at an average value determined as follows: when the  
output combination of L1 and COUT is large enough to maintain a low ripple on IFB (approximately less  
than 100 mV), Iout(avg) can be calculated:  
VIFBTH  
Iout(avg) =  
RCS  
Having load current programmable from 350 mA to 1.5 A, series and parallel combinations of resistors  
must be used to properly set the current, as well as distribute power accordingly. Equivalent  
resistances for each current setting were calculated as follows:  
0.5V  
R350mA  
R700mA  
=
=
=1.43 Ω  
= 0.71Ω  
350 mA  
0.5V  
700 mA  
0.5V  
R1A =  
= 0.5 Ω  
1 A  
0.5V  
1.5 A  
R1.5A  
=
= 0.33 Ω  
Since some of these equivalent values of resistance are not available, series and parallel combinations  
are used, and they are specified as follows (all combinations use standard value resistors: 1.43 , 0.56  
, and 0.47 ):  
R350mA =1.43 Ω  
R700mA = 0.71Ω ≈ (1.43 ||1.43 ) = 0.715 Ω  
R1A = 0.5 Ω ≈ (0.47 Ω + 0.56 ) || (0.47 Ω + 0.56 ) = 0.515 Ω  
R1.5A = 0.33 Ω ≈ (0.47 Ω + 0.56 ) || (0.47 Ω + 0.56 ) || (0.47 Ω + 0.56 ) = 0.343 Ω  
Although some of the series and parallel combinations do not yield the exact resistance needed, for all  
tolerance purposes, they are accurate enough. For this evaluation board, an extremely tight current  
regulation was achieved with a worst case result of ±1.2% for the 350 mA setting as the bus voltage  
was swept from 40 V to 170 V. Likewise a precise regulation of ±0.25% was maintained for a varying  
load voltage from 16 V to 24 V for the 350 mA current setting.  
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1600  
1400  
1200  
1000  
800  
600  
400  
200  
0
±0.3%  
±0.5%  
±0.6%  
±1.2%  
350mA  
1A  
700mA  
1.5A  
VIN (V)  
30  
80  
130  
180  
Fig. 5: Vout = 16 V, L1 = 470 µH, COUT = 33 µF  
1600  
1400  
1200  
1000  
800  
600  
400  
200  
0
±0.1%  
±0.17%  
±0.13%  
350mA  
700mA  
1A  
±0.25%  
1.5A  
10  
15  
20  
VOUT (V)  
25  
30  
Fig. 6: Vbus = 100 V, L1 = 470 µH, COUT = 33 µF  
3. Frequency selection  
The frequency in the IRS254(0,1) is free running and maintains current regulation by quickly adapting  
to changes in input and output voltages. There is no need for additional external components to set the  
frequency as seen with most oscillators, resulting in a part reduction. The frequency is determined by  
L1 and COUT, as well as the input/output voltages and load current. The selection of the frequency will  
be a trade-off between system efficiency, current control regulation, size, and cost.  
The higher the frequency, the smaller and lower the cost of L1 and COUT, the higher the ripple, the  
higher the FET switching losses, which becomes the driving factor as VBUS increases to higher  
voltages, the higher the component stresses and the harder it is to control the output current.  
With an input voltage as high as 170 V, the targeted frequency was determined to be between 50 kHz  
and 75 kHz. Within this operating spectrum all components can easily handle their associated power  
losses.  
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4. Output L1 and COUT selection  
To maintain tight hysteretic current regulation L1 and COUT need to be large enough to maintain the  
supply to the load during tHO,on and avoid significant undershooting of the load current, which in turn  
causes the average current to fall below the desired value.  
First, we are going to look at the effect of the inductor when there is no output capacitor to clearly  
demonstrate the impact of the inductor. In this case, the load current is identical to the inductor current.  
Figure 7 shows how the inductor value impacts the frequency over a range of input voltages. As can be  
seen, the input voltage has a great impact on the frequency and the inductor value has the greatest  
impact at reducing the frequency for smaller input voltages.  
Figure 8 shows how the variation in load current increases over a span of input voltage, as the  
inductance is decreased. Figure 9 shows the variation of frequency over different output voltages and  
different inductance values. Finally Fig. 10 shows how the load current variation increases with lower  
inductance over a range of output voltages.  
375  
325  
275  
470uH  
680uH  
225  
1mH  
1.5mH  
175  
VIN (V)  
30  
80  
130  
180  
Fig. 7: Iout = 350 mA, Vout = 16.8 V, COUT = 0 µF  
The output capacitor can be used simultaneously to achieve the target frequency and current control  
accuracy. Figure 11 shows how the capacitance reduces the frequency over a range of input voltage. A  
small capacitance of 4.7 µF has a large effect on reducing the frequency. Figure 12 shows how the  
current regulation is also improved with the output capacitance. There is a point at which continuing to  
add capacitance no longer has a significant effect on the operating frequency or current regulation, as  
can be seen in Figs. 12 & 13.  
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400  
390  
380  
370  
360  
350  
340  
330  
470uH  
680uH  
1mH  
1.5mH  
VIN (V)  
30  
80  
130  
180  
Fig. 8: Iout = 350 mA, Vout = 16.8 V, COUT = 0 µF  
400  
380  
360  
340  
320  
300  
280  
260  
240  
220  
200  
470uH  
680uH  
1mH  
1.5mH  
13  
18  
23  
OUT (V)  
28  
33  
V
Fig. 9: Iout = 350 mA, Vin = 50 V, COUT = 0 µF  
345  
343  
341  
339  
337  
335  
333  
331  
329  
327  
325  
470uH  
680uH  
1mH  
1.5mH  
13  
18  
23  
VOUT (V)  
28  
33  
Fig. 10: Iout = 350 mA, Vin = 50 V, COUT = 0 µF  
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1000  
100  
10  
0uF  
4.7uF  
22uF  
47uF  
10uF  
33uF  
VIN (V)  
30  
80  
130  
180  
Fig. 11: Iout = 350 mA, Vout = 16.8 V, L = 470 µH  
390  
380  
370  
360  
350  
340  
330  
0uF  
4.7uF  
10uF  
22uF  
33uF  
47uF  
30  
50  
70  
90  
110  
130  
150  
170  
VIN (V)  
Fig. 12: Iout = 350 mA, Vout = 16.8 V, L = 470 µH  
400  
350  
300  
250  
200  
150  
100  
50  
40V  
100V  
160V  
0
0
10  
20  
30  
40  
50  
Capacitance (µF)  
Fig. 13: Iout = 350 mA, Vout = 16.8 V, L = 470 µH  
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The addition of the COUT is essentially increasing the amount of energy that can be stored in the output  
stage, which also means it can supply current for an increased period of time. Therefore by slowing  
down the di/dt transients in the load, the frequency is effectively decreased.  
With the COUT capacitor, the inductor current is no longer identical to that seen in the load. The  
inductor current will still have a perfectly triangular shape, where as the load will see the same basic  
trend in the current, but all sharp corners will be rounded with all peaks significantly reduced, as can  
be seen in Figs. 14 & 13.  
Fig. 14: Iout = 350 mA, Vin = 100 V, Vout = 16.85 V, L = 470 µH, COUT = 33 µF  
Fig. 15: Iout = 350 mA, Vin = 100 V, Vout = 16.85 V, L = 470 µH, COUT = 33 µF  
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L1 and COUT need to be chosen so that it stores enough energy to supply the load during tHO,on while  
maintaining current control accuracy. A lower value of L1 will require a larger value of COUT  
.
Since this evaluation board is designed to handle a load current only as high as 1.5 A, off the shelf  
inductors are available. Instead, to minimize or eliminate any effects of eddy currents, a custom  
inductor for this application was designed by VOGT. High value (in the order of 1 mH or more)  
inductors that can handle this amount of current are not readily available and tend to be bulky and  
costly. With too small of an inductor (in the order of 100 µH or less), the COUT capacitor would need  
to be in the order of hundreds of micro farads to maintain good current regulation. Additionally, with a  
smaller inductance, the ripple current seen by the capacitor would be quite large, shortening the life of  
the capacitor, if an electrolytic were used.  
Because of these considerations an inductor of 470 µH and an output capacitance of 33 µF were  
chosen to accommodate the 1.5 A load current. The current ripple associated with 470 µH is relatively  
small, so the board can be operated with or without output capacitance at the lower current ratings.  
5. FET vs. diode for the low-side switch  
The IRS254(0,1) has been designed so that it can drive a low-side FET and a high-side FET. If the use  
of two FETs for the half-bridge proves to be a cost issue, the low-side FET can be replaced by a  
freewheeling diode as shown in Fig. 16. Of course this may yield a lower cost system, but there are  
some efficiency tradeoffs to be considered, particularly for higher load currents. The system efficiency  
is directly influenced by several system parameters including operating frequency, load current, and  
input voltage.  
A major parameter to consider is the reverse recovery time of the diode in comparison to the body  
diode of the FET it replaces. The diode intrinsically has a much shorter reverse recovery time since the  
device is specifically designed for this, where as the body diode is a parasitic element that originates  
from basic processing technology and typically has inferior characteristics, in terms of forward drop,  
reverse recovery, and power handling capabilities.  
Fig. 16: Alternate IRS254(0,1) Time-Delayed Hysteretic Controlled Evaluation Board Schematic  
Note: Rout is needed only in few applications  
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The reverse recovery problem is incurred during the deadtime after the low-side FET has been on and  
conducting current. During this deadtime the low-side FET is off, but the body diode is freewheeling  
and providing current to the load. Since the body diode is conducting current, carriers are present and  
will eventually need to be recombined, leading to reverse recovery. When the high-side FET turns on,  
the VS node is almost instantly pulled from COM to VBUS and the low-side FET or the freewheeling  
diode conducts current from VS to ground due to the reverse recovery effect, potentially resulting in  
large power losses, overheating of the low-side switching component and component stress, as can be  
seen in Figs. 17 & 18. Since the power diode has a much shorter reverse recovery time, the diode will  
conduct current for a significantly shorter period and have lower power losses. At lower frequency  
and lower load current, the long recovery time associated with the FET body diode may not be an  
issue. For higher frequency higher current applications, a diode could provide lower power losses with  
respect to a FET.  
In the evaluation board, the reverse recovery current peaks using a low-side FET would be on the order  
of 8 A, which puts a lot of stress on the components, not to mention the increased operating  
temperature. By replacing the low-side FET with an appropriate freewheeling diode, the reverse  
recovery peaks can be reduced and limited to 4.5 A. The frequency was also selected to keep the diode  
reverse recovery associated power losses low.  
With the inclusion of a freewheeling diode instead of a low-side FET there is a need for RS3 and DVCC  
.
Without an initial pulse to come from LO establishing a ground reference for CBOOT to charge, an  
alternate ground reference must be established. There are two paths that could potentially serve this  
role, one is through RS2 and the other is through the open-circuit components, ROV1 and ROV2. The  
most versatile path is through ROV1 and ROV2 since there are no constraints along this path tied to the  
chip’s turn on threshold. By making these two resistors, that are already serving function to the circuit,  
a bit smaller, the capacitor now has a low resistive path for which to charge. RS3 allows this charging  
path to exist without any interference from the chip VCC, likewise DVCC also allows this path to remain  
isolated. As the bus voltage is increased, the path will allow CBOOT to fully charge and remain charged  
until the chip comes out of UVLO. At which time the self powering feature will take over after the  
first pulse from HO, and the ground reference will then be created by the freewheeling diode.  
Fig. 17: Using a low-side FET, Vin = 100 V, Iout = 1.5 A, Vout = 17 V  
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Fig. 18: Using a diode on the low-side, Vin = 100 V, Iout = 1.5 A, Vout = 17 V  
Fig. 19: Low-side FET vs. low-side diode comparison, Vin = 100 V, Iout = 1.5 A, Vout = 17 V  
The bus voltage is also of importance since it will determine how long the low-side FET, or the  
freewheeling diode will be conducting. If the bus voltage is very large in comparison to the output, the  
low-side FET or diode will be conducting for the majority of the switching period. A FET has much  
lower on-state losses due to the low RDS,on, where as high voltage diodes rarely have forward drops less  
than 1 V. If the load current is in the order of 1 A or 1.5A, a FET may have low on-state losses, where  
as the diode may experience larger conduction losses. If the load current is only a few hundred  
milliamps, the losses observed in the diode may not be a concern, and the cost savings of a diode could  
be exercised. For system efficiency, the forward conduction losses of a diode can also be compared to  
the reverse recovery losses with a low-side FET. For this evaluation board, it was found that  
conduction losses were less than reverse recovery losses when running at 1.5 A and therefore uses and  
freewheeling diode.  
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Fig. 20: Low-side FET and low-side diode comparison, Vin = 100 V, Iout = 1.5 A, Vout = 17 V  
The most efficient solution would be to put the FET in parallel with the diode in the low-side position.  
In this case, during the deadtime, instead of the body diode freewheeling, the additional diode would  
be conducting. This will always be the case as long as the forward drop of the external diode is less  
than that of the body diode. If costs permit, a diode in parallel with an IGBT could also be an option.  
A detailed, evaluation of system needs and cost should be performed prior to choosing a FET or diode  
for the low-side. Although a diode is cheaper, in certain cases the associated power losses may require  
a heatsink, nullifying the cost reduction of using a diode. Likewise there are conditions where a FET  
may prove less efficient, in which case more money will be spent on the FET as well as the heatsink to  
keep it cool. The evaluation board is provided with a freewheeling diode and the footprint for a low-  
side FET has been provided to replace the diode with a FET if the application requires it. It is not  
recommended to replace the diode with a FET for the 1 A and 1.5 A operation because of the  
associated reverse recovery power losses. If replacing the diode with a FET is a requirement, it might  
be beneficial to move the diode heatsink to the high-side FET.  
In terms of choosing the correct FET, it is best to use a FET rated as low as possible considering what  
is needed in the application. FET parameters degrade as the voltage ratings go up. Therefore, if a 600  
V FET is used in a 200 V application, extra losses may be incurred due to a component that far  
exceeds the requirements. If using two FETs, the next parameter to be considered is the reverse  
recovery time. Obviously FETs will not have a reverse recovery time comparable to diodes, but a  
good FET reverse recovery time will be in the order of 150 ns to 200 ns. The two remaining  
parameters to consider are direct trade-offs of each other, on resistance and gate charge. If the FET has  
a rather low gate capacitance, the die size will be small, but this will result in a larger on resistance  
which could potentially be a problem for high current applications. On the other hand, if the FET has a  
large gate capacitance, the die will be large and the FET will have a low on resistance, but it will be  
more difficult to turn on the FET which will also stress the IC. There has to be a direct compromise  
between the two, typically the best solution is a FET with a relatively low RDS,on and a medium sized  
gate capacitance, much like the device chosen for this application  
6. VCC supply  
Since the IRS2540 (IRS2541) is rated for 200 V (600 V), VBUS can reach values of this magnitude. If  
only a supply resistor to VBUS is used, it will experience high power losses. For higher voltage  
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applications an alternate  
supply scheme utilizing a resistor feed-back (RS2) from the output needs  
VCC  
to be implemented, as seen in Figs. 1 & 16.  
The resistance between VBUS and  
(RS1) should be large enough to minimize the current sourced  
VCC  
directly from the input voltage line; value should be on the order of several kilo ohms. Through this  
supply resistor a current will flow to charge the capacitor. Once the capacitor is charged up to the  
VCC  
threshold, the IRS254(0,1) begins to operate, activating the LO and HO outputs. After the first  
VCCUV+  
few cycles of switching, the resistor RS2 connected between the output and  
will take over and  
VCC  
source current for the IC. The RS2 resistor provided in the evaluation board has been designed for an  
output of roughly 20 V. If a higher output voltage is desired, RS2 will need to be redesigned and  
adjusted accordingly.  
A 10 µF capacitor has been used for stabilizing VCC of the chip. Such a large capacitance makes the  
chip immune to any large low frequency ripple that may be observed on VBUS due to a rectified  
waveform. There are also other benefits associated with using such a large capacitance, of which will  
be discussed later.  
With having all input and output voltages defined for the evaluation board, enough information is  
provided to calculate values for RS1, RS2, and RS3 (see Fig. 23 for component definition). All three  
supply resistors were chosen to be 1 W devices since they source all current to the chip. By making  
each component 1 W, the work in supplying the chip can be split up equally, making it a more robust  
solution, instead of baring the entire task on one component. Doing this also allows the chip to turn on  
at a lower bus voltage. Assuming that a 14 V external zener diode will be used on VCC, exact values of  
RS1, RS2, and RS3 were calculated as follows (values were calculated to operate the components just  
below half their rated power):  
V 2  
P =  
R
RS1  
2
(
VBus 14V  
)
max  
1
W =  
2
RS1  
2
2
(
VBus 14V  
)
(
170V 14V  
)
max  
RS1 =  
=
1
1
W
W
2
2
RS1 = 48.6 kΩ ≈ 56 kΩ  
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RS3  
min duty ratio 10%  
2
(
10.1  
)
(
VBus 14 V  
)
max  
1
W =  
2
RS3  
2
2
(
10.1  
)
(
VBus 14 V  
)
(
10.1  
)
(
170 V 14 V  
)
max  
RS3  
=
=
1
1
W
W
2
2
RS1 = 43.8 kΩ ≈ 47 kΩ  
RS2  
2
(
VOut 14 V  
)
max  
1
W =  
2
RS 2  
2
2
(
VOut 14 V  
)
(
30 V 14 V  
)
max  
RS 2  
=
=
1
1
W
W
2
2
RS1 = 512 Ω ≈ 1 kΩ  
7. VBS supply  
The bootstrap diode (DBOOT) and supply capacitor (CBOOT) comprise the supply voltage for the high-  
side driver circuitry. To guarantee that the high-side supply is charged up before operation commences,  
the first pulse from the output drivers comes from the LO pin. During undervoltage lock-out mode, the  
high- and low-side outputs are both held low.  
During an open-circuit condition, without the watchdog timer, the HO output would remain high at all  
times and the charge stored in CBOOT would slowly leak until reaching zero, thus eliminating the  
floating power supply for the high-side driver. To maintain sufficient charge on CBOOT, a watchdog  
timer has been implemented. In the condition where VIFB remains below VIFBTH, the HO output will be  
forced low roughly after 20 µs and the LO output forced high. This toggling of the outputs will last for  
1 µs to maintain and replenish sufficient charge on CBOOT  
.
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Fig. 21: Illustration of Watchdog Timer  
The bootstrap capacitor value needs to be chosen so that it maintains sufficient charge for at least the  
20 µs interval until the watchdog timer allows the capacitor to recharge. If the capacitor value is too  
small, the charge will fully dissipate in less than 20 µs. The bootstrap capacitor should be at least 100  
nF. A larger value within reason can be used if preferred.  
The bootstrap diode should be a fast recovery, if not an ultrafast recovery component to maintain good  
efficiency. Since the cathode of the bootstrap diode will be switching between COM and VBUS + 14 V,  
the reverse recovery time of this diode is of critical importance. For additional information concerning  
the bootstrap components, refer to the Design Tip (DT 98-2), “Bootstrap Component Selection For  
Control ICs” at www.irf.com under Design Support.  
8. Enable pin  
The enable pin can be used for dimming and open-circuit protection. When the ENN pin is held low,  
the chip remains in a fully functional state with no alterations to the operating environment. To disable  
the control feedback and regulation, a voltage greater than VENTH (approximately 2.5 V) needs to be  
applied to the ENN pin. With the chip in a disabled state, HO output will remain low, where as the LO  
output will remain high to prevent VS from floating, in addition to maintaining charge on the bootstrap  
capacitor. The threshold for disabling the IRS254(0,1) has been set to 2.5 V to enhance immunity to  
any externally generated noise, or application ground noise. This 2.5 V threshold also makes it ideal to  
receive a drive signal from a local microcontroller.  
Dimming mode  
To achieve dimming, a signal with constant frequency and set duty cycle can be fed into the EN pin.  
There is a direct linear relationship between the average load current and duty cycle. If the ratio is  
50%, 50% of the maximum set light output will be realized. Likewise if the ratio is 30%, 70% of the  
maximum set light output will be realized. A sufficiently high frequency of the dimming signal must  
be chosen to avoid flashing or “strobe light” effect. A signal on the order of a few kHz should be  
sufficient. For this evaluation board, a fully adjustable (0% to 100% duty cycle) PWM wave generator  
has been designed but not included in the layout. The following design is a recommended enable  
signal generator.  
RD-0608  
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VBUS  
RS2  
R1  
R3  
R2  
VCC  
OUT2  
IN2(-)  
IN2(+)  
OUT1  
CVCC4  
R5  
C1  
C2  
IC2  
1
2
3
4
8
7
6
5
R6  
IN1(-)  
IN1(+)  
CVCC3  
DEN2  
Out to  
ENN pin  
GND  
POT1  
R4  
COM  
Fig. 22: Suggested PWM Driver (not included in IRPLLED1)  
If an external supply for VCC is used, the minimum amount of dimming achievable (light output  
approaches 0%) will be determined by the “on” time of the HO output, when in a fully functional  
regulating state. To maintain reliable dimming, it is recommended to keep the “off” time of the enable  
signal at least 10 times that of the HO “on” time. For example, if the application is running at 75 kHz  
with an input voltage of 100 V and an output voltage of 20 V, the HO “on” time will be 3.3 µs (one-  
fourth of the period – see calculations below) according to standard buck topology theory. This will  
set the minimum “off” time of the enable signal to 33 µs.  
Vout  
Vin  
20 V  
Duty Cycle =  
100 =  
*100 = 20%  
= 3.3 µs  
100 V  
1
HOon time = 20%*  
75 kHz  
If the chip is supplied from the output, a large enough capacitor on VCC is required to maintain  
sufficient current while in a disabled state. For this evaluation board, where the IC supply comes from  
the output, a 10 µF capacitor is used to ensure continued proper operation while disabled, the output is  
capable of dimming down to roughly 10 V. A “strobe light” effect in the LEDs may be observed if  
V
CC drops too much or if the dimming frequency is too low.  
RD-0608  
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Enable Duty Cycle Relationship to Light Output  
100  
90  
80  
70  
60  
50  
40  
30  
20  
10  
0
0
10  
20  
30  
40  
50  
60  
70  
80  
90  
100  
Percentage of Light Output  
Fig. 23: Light Output vs. Enable Pin Duty Cycle  
Fig. 24: IRS2540 Dimming Signals  
Since the IRS254(0,1) does not include an onboard oscillator, a soft start feature is not possible. This  
is only a concern when operating in the dimming mode. Since PWM dimming is required of LEDs,  
the output is essentially turning on and off at a rate of the dimming frequency. In the absence of soft  
start, a large spike of current would be observed in the load each time the output is turned on. This  
current spike stresses the load possibly decreasing its overall lifetime. The IRPLLED1 includes a  
jumper setting to define whether or not the board is being used in the dimming mode. This two  
position jumper will allow the designer to either include or exclude the resistor Rout, which is in series  
with the output capacitor. The inclusion of this resistor will sufficiently damp the output stage, such  
that output current spikes are significantly reduced or eliminated. The presence of such current spikes  
may cause the inductor to hum or buzz, the emitted sound will be that of the dimming frequency. The  
inrush of current causes mechanical movement in the inductor which can be heard if the PWM signal  
is within the audible range of the human ear. The effects of adding in Rout can be seen in Figs. 25 – 28.  
RD-0608  
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Fig. 25: Load Current Spike Excluding Rout  
Iout = 350 mA, Vin = 100 V, Vout = 17 V  
Fig. 26: Load Current Ripple Excluding Rout  
I
out = 350 mA, Vin = 100 V, Vout = 17 V  
Although the inclusion of the resistor will minimize or eliminate the load current spikes, the overall  
current regulation and operating frequency will be slightly compromised. The resistor will reduce the  
overall effectiveness of the output capacitor which means the switching frequency will marginally  
increase. Likewise the output ripple current will also increase, which ultimately leads to a larger  
current regulation tolerance. Although the overall current regulation capabilities may decrease with  
the inclusion of this resistor, the actual stability of the PWM dimming signal will still be the dominant  
factor of the overall output current regulation capabilities.  
RD-0608  
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Fig. 27: Load Current Spike Including Rout (5 )  
out = 350 mA, Vin = 100 V, Vout = 17 V  
I
Fig. 28: Load Current Ripple Including Rout (5 )  
out = 350 mA, Vin = 100 V, Vout = 17 V  
I
Open-circuit protection mode  
By using the suggested voltage divider, capacitor, and zener diode, the designer can virtually clamp the  
output voltage at any desired value. If there is no load and the output clamp is not utilized, the positive  
output terminal will float at the high-side input voltage. The open load clamp is recommended if the  
load is disconnected and then reconnected without shutting down the driver. When the load is  
reconnected with power on, the load would see the entire bus voltage for a short period of time. The  
RD-0608  
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open-circuit clamp minimizes the amount of stress seen by the load under such circumstances by  
clamping the voltage much lower than VBUS  
.
Fig. 29: Open-Circuit Protection Scheme  
In open-circuit condition, switching will still occur between the HO and LO outputs, whether due to  
the output voltage clamp or to the watchdog timer. In this state, rather than regulating the current with  
the feedback pin, the output voltage will be loosely regulated via the enable pin. Transients and  
switching will be observed at the positive output terminal as seen in Fig. 30. The difference in signal  
shape, between the output voltage and the IFB, is due to the capacitor CEN used to form the voltage  
clamp. The repetition of the spikes can be reduced by simply increasing the cap size. If VBUS is  
significantly larger than the desired output voltage clamp, the output voltage will become a function of  
V
BUS. This is because of the intrinsic delays of the chip (tLO,on, tLO,off, tHO,on, and tHO,off) along with the  
minimum HO on time. If the load is removed, the output will clamp at the desired voltage. Then if the  
bus voltage is increased, there could be a proportional change in the clamped voltage. This is not seen  
as an issue since the open-circuit clamp is strictly a safety feature to reduce the stress seen by the load,  
if disconnected and reconnected without a power down.  
Fig. 30: Open-Circuit Fault Signals, with Clamp  
RD-0608  
22  
www.irf.com  
The two resistors ROV1 and ROV2 form a voltage divider for the output, which is then fed into the  
cathode of the zener diode DOV The diode will only conduct, flooding the enable pin, when its  
.
nominal voltage is exceeded. The chip will enter a disabled state once the divider network produces a  
voltage at least 2.5 V greater than the zener rating. The capacitor CEN serves only to filter and slow the  
transients/switching at the positive output terminal. The clamped output voltage can be determined by  
the following analysis.  
(
2.5V + DZ
)(
R1 + R2  
)
Vout  
=
R2  
DZ = Zener Diode Nominal Rated Voltage  
DOV has been chosen to be a 7.5 V zener diode. ROV2 has also been set to 390 to help provide a low  
resistive charging path for CBOOT as previously discussed. It was also decided to clamp the output  
voltage at 30 V, this is sufficiently larger than the predefined maximum load voltage of 24 V as to not  
cause any erroneous shut-down, while it is also well within the specifications of the 100 V rated output  
stage. Having arbitrarily chosen these parameters, ROV1 was calculated as follows:  
(
2.5V + DZ
)(
ROV1 + ROV 2  
)
Vout  
=
ROV 2  
Vout ROV 2  
30 V 390 Ω  
2.5V + 7.5V  
ROV1  
=
ROV 2  
=
390 Ω = 780 Ω  
(
2.5V + DZ  
)
(
)
ROV1 820 Ω  
9. Other design considerations  
Filtering  
The RC filter on the IFB pin is only used to remove high frequency transients associated with the FET  
switching. The corner frequency of this filter was left high enough to prevent any further distortion of  
the feedback.  
The input filter is a low-pass filter. Its main objective is to prevent ringing of comparable frequency  
on Vbus. Exact values of capacitance and inductance are not of critical importance, so long as filtering  
is accomplished. In addition to the electrolytic that is used for filtering on the bus, there is also a small  
ceramic for high frequency signals. Ceramic capacitors typically have low ESR such that they are  
more ideal for high frequency filtering.  
VCC filtering was accomplished by typical means of using a small 100 nF ceramic, an additional  
electrolytic was used in case of dimming. The larger electrolytic was placed in event a long enable  
signal is given. With this larger capacitance, the VCC supply will remain for a prolonged period of time  
so the outputs will remain disabled, and the chip will not shut down.  
RD-0608  
23  
www.irf.com  
The ENN filter capacitor was arbitrarily chosen to be 100 nF, this helps slow the rate of switching  
during open load conditions.  
The IRS254(0,1) was specifically designed to handle low frequency ripples on VBUS. Its capability to  
handle such ripple makes it ideal for an offline rectified waveform. However if high voltage (on the  
order of 5 V to 10 V) high frequency oscillations (greater than or close to the operating frequency) are  
present on VBUS, it is recommended to implement an input filter. If these high frequency signals are  
present on VBUS the IRS254(0,1) will still continue to regulate the current through the load, but  
abnormal switching of LO and HO may be observed. This poses a problem in terms of switching  
losses. As previously discussed, one may need or want to control the operating frequency to control  
the systems efficiency, but if LO and HO randomly switch, it may negate all attempts to control the  
frequency. Of course the root of this problem can be significantly contributed through PCB layout, but  
it is also a function of the load current. If filters on IFB and VCC are not placed correctly these high  
frequency ripples will couple to the chip and appear within the control loop. Also if the load current is  
on the order of 1 A or 1.5 A, when HO turns on, the load immediately tries to pull the rated current.  
Since the circuit supply is not usually close by, the capacitance of the input wire is not enough to  
compensate for this large pull of current, this will result in oscillations or change in potential on the  
input line. Since the switching element of the circuit is one cause of these oscillations, it is easy to see  
how likely the presence of high frequency oscillations are. To alleviate the circuit of such possible  
problems, it is much easier to implement an input filter. The input filter will also greatly improve the  
circuits EMC performance.  
EMC performance  
The IRS254(0,1) demo board has not been EMC tested. Input and output filters can be used to reduce  
the conducted emissions to below the limits of the applicable EMC standard as needed. All inductors  
may require a powdered iron core rather than ferrite, it can handle a much larger current before  
saturating, needs are pending on the load current. If EMC is of critical importance, one may prefer to  
use one FET and one diode, in contrast to a half-bridge driver. The reverse recovery time for a diode  
is inherently shorter than that of a FET. This will help in reducing transients observed in the  
switching elements resulting in better EMC performance.  
Layout considerations  
It is very important when laying out the PCB for the IRS254(0,1) to consider the following points:  
1.  
2. The feedback path should be kept to a minimum without crossing any high frequency lines.  
3. OUT should be as close to the main inductor as possible.  
CVCC2 and CF must be as close to the IC as possible.  
C
4. All traces that form the nodes VS and VB should be kept as short as possible.  
5. All signal and power grounds should be kept isolated from each other to prevent noise from  
entering the control environment. It’s a general rule of thumb that all components associated  
with the IC should be connected to the IC ground with the shortest path possible.  
6. All traces carrying the load current need to be adjusted accordingly.  
7. Gate drive traces should also be kept to a minimum.  
10. Design procedure summary  
1. Determine the systems requirements: input/output voltage and current needed  
2. Calculate current sense resistor  
3. Determine the operating frequency required  
4. Select L1 and COUT so that they maintain supply into the load during tHO,on  
.
RD-0608  
24  
www.irf.com  
5. Select switching components (FET/freewheeling diode) to minimize power losses  
6. Determine VCC and VBS supply components  
7. Add filtering on the input, IFB and ENN as needed  
8. Fine tune components to achieve desired system performance  
11. Bill of materials  
Careful selection of the components will significantly increase the reliability of the product,  
particularly for the capacitors. These need to be rated for at least 100 ºC and a proper voltage. As in  
most electronic power applications, capacitors and resistors are the components most likely to fail due  
to stress over time and high operating temperatures. All capacitors connected to the output in this  
evaluation board have only a rating of 100 V. These capacitors may also need to be changed if the  
load is significantly different from the tested load.  
RD-0608  
25  
www.irf.com  
Device  
Type  
# of  
devices  
Item  
Description  
Part #  
UVZ1E100MDD  
Manufacurer  
Nichicon  
Reference  
CVCC1  
1
2
C
C
10uF, 25V, Radial  
100nF, 200V, 1812  
1
1
BC Components  
CBUS2  
VJ1812Y104KXCAT  
CVCC2, CBOOT,  
CEN  
3
C
100nF, 50V, 0805  
VJ0805Y104KXATW1BC  
BC Components  
3
4
5
C
C
33uF, 100V  
1nF, 50V, 0805  
47uF, 200V  
200V, 1A  
UVZ2A330MPD  
VJ0805Y102KXACW1BC  
UVZ2D470MHD  
MUR120T3  
Nichicon  
BC Components  
Nichicon  
On Semi  
Diodes Inc  
IR  
1
1
1
1
2
1
1
1
1
1
1
COUT  
CF  
6
C
CBUS1  
DBOOT  
DEN1, DVCC  
D1  
7
D
8
D
Mini Melf  
LL4148  
9
D
300V, 8A  
8ETH03  
10  
11  
12  
13  
14  
DZ  
DZ  
L
14V, 0.5W, Mini Melf  
7.5V, 0.5W, Mini Melf  
470uH  
Diodes Inc  
Diodes Inc  
VOGT  
DCLAMP  
DOV  
ZMM5244B-7  
ZMM5236B-7  
IL 050 321 31 01  
RFB1010-471  
MCR10EZHF10R0  
L1  
L
470uH  
Coilcraft  
Rohm  
L2  
R
10ohm, 1%, 0805  
RG1  
RCS2, RCS4,  
RCS6  
15  
16  
R
R
0.56ohm, 1%, 1206  
0.47ohm, 1%, 1206  
ERJ-8RQFR56V  
ERJ-8RQFR47V  
Panasonic  
Panasonic  
3
3
RCS1, RCS3,  
RCS5  
17  
18  
19  
20  
21  
22  
23  
24  
25  
26  
27  
28  
29  
30  
31  
32  
33  
34  
35  
36  
37  
38  
39  
40  
41  
42  
R
R
R
R
R
R
R
R
IC  
1.43ohm, 1%, 1206  
100ohm, 1%, 0805  
9C12063A1R43FGHFT  
MCR10EZHF1000  
Yageo  
2
1
1
1
1
1
1
1
1
1
1
2
2
1
1
1
1
1
3
RCS7, RCS8  
RF  
Rohm  
390ohm, 5%, 1/2W, 2010 ERJ12ZYJ391  
820ohm, 5%, 1/2W, 2010 ERJ12ZYJ821  
Panasonic  
Panasonic  
Phoenix Passive  
Phoenix Passive  
Phoenix Passive  
Phoenix Passive  
IR  
ROV2  
ROV1  
RS2  
1k, 5%, 1W  
47K, 5%, 1W  
56K, 5%, 1W  
5ohm, 5%, 1W  
IRS2540/1  
5073NW1K000J12AFX  
5073NW47K00J12AFX  
5073NW56K00J12AFX  
5073NW5R100J12AFX  
IRS2540/1  
RS3  
RS1  
Rout  
In Socket  
IC1  
Socket 8 Pin DIP  
2-641260-1  
Amp  
M
T
200V, 16A, TO-220  
IRFB17N20D  
5005  
IR  
M1  
PC Compact, red  
PC Compact, black  
PC Compact, yellow  
Heatsink  
Keystone  
Keystone  
Keystone  
IERC  
T1, T4  
T2, T5  
T3  
T
5006  
T
5009  
H
7-340-1PP-BA  
B
PCB  
J
Jumper, 10 Pos.  
Jumper, 2 Pos.  
Shorting Jumper  
Not Fitted  
929836-09-05-ND  
929836-09-02-ND  
929950-00-ND  
3M  
3M  
3M  
Jset  
J
Jdim  
SJ  
D
DIFB  
RIFB  
M2  
R
Not Fitted  
M
TH  
W
SC  
N
Not Fitted  
TO-220 Insulating Thermal P  
Shoulder Washer  
Screw, 4-40, 0.5", Zinc  
Nut, 4-40, Hex, Zinc  
Berquist  
2
2
1
1
SP600-54  
Berquist  
3049  
H346-ND  
H216-ND  
Building Fasteners  
Building Fasteners  
RD-0608  
26  
www.irf.com  
Enable Signal Generator (not included)  
Device  
Type  
# of  
devices  
Item  
Description  
Part #  
Manufacurer  
Panasonic  
Reference  
1
2
C
10uF, 25V, Radial ECEA1EKG100  
1
1
2
1
1
1
1
1
2
2
1
1
CVCC3  
CVCC4  
C1, C2  
DEN2  
R6  
C
100nF, 50V, 0805 VJ0805Y104KXATW1BC  
BC Components  
BC Components  
Diodes Inc  
Rohm  
3
C
1nF, 50V, 0805  
Mini Melf  
VJ0805Y102KXACW1BC  
LL4148  
4
D
5
R
1k, 1%, 0805  
6.8k, 1%, 0805  
10k, 1%, 0805  
20k  
MRC10EZHF1001  
MRC10EZHF6801  
MRC10EZHF1002  
MRC10EZHF2002  
MRC10EZHF7502  
MRC10EZHF1003  
M64W103KB40  
LM393D  
6
R
Rohm  
R5  
7
R
Rohm  
R4  
8
R
Rohm  
R2  
9
R
75k  
Rohm  
R1, R3  
RS2  
10  
11  
12  
R
100k  
Rohm  
POT  
IC  
10k, 10-turn  
Comparator  
BC Components  
Texas Instruments  
POT1  
In Socket  
Amp Tyco  
Electronics  
13  
Socket 8 Pin DIP  
2-641260-1  
1
IC2  
12. PCB Layout  
Top Overlay  
Top Metal  
RD-0608  
27  
www.irf.com  
Bottom Overlay  
Bottom Metal  
IR WORLD HEADQUARTERS: 233 Kansas St., El Segundo, California 90245 Tel: (310) 252-7105  
Data and specifications subject to change without notice. 9/8/2006  
RD-0608  
28  
www.irf.com  

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